\(\frac{2}{5.7}+\frac{5}{7.12}+\frac{8}{12.20}+\frac{3}{140}\)
\(=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{12}+\frac{1}{12}-\frac{1}{20}+\frac{3}{140}\)
\(=\frac{1}{5}-\frac{1}{20}+\frac{3}{140}\)
\(=\frac{3}{20}+\frac{3}{140}\)
\(=\frac{6}{35}\)