\(\left(\dfrac{2}{3}\right)^3\cdot\left(-\dfrac{3}{4}\right)^2=\dfrac{8}{27}\cdot\dfrac{9}{16}=\dfrac{1}{6}\)
Đúng 3
Bình luận (2)
\(\left(\dfrac{2}{3}\right)^3\cdot\left(-\dfrac{3}{4}\right)^2=\dfrac{8}{27}\cdot\dfrac{9}{16}=\dfrac{1}{6}\)