Question

(2/3 - x)² - 1/9 = 0

Answer 1

`(2/3 -x)^2 - 1/9=0`

`(2/3-x)^2 = 0+1/9`

`(2/3-x)^2 = 1/9`

`(2/3-x)^2 = (1/3)^2`

`@TH1`

`2/3-x = 1/3`

`x=2/3 -1/3`

`x=1/3`

`@TH2:`

`2/3-x=-1/3`

`x=2/3-(-1/3)`

`x=2/3+1/3`

`x=3/3`

`x=1`

Vậy`x = {1/3;1}`

Answer 2

\(\rightarrow\left(\dfrac{2}{3}-x\right)^2=\dfrac{1}{9}\\ \left(\dfrac{2}{3}-x\right)^2=\left(\dfrac{1}{3}\right)^2\\ \rightarrow\dfrac{2}{3}-x=\dfrac{1}{3}\\ x=\dfrac{2}{3}-\dfrac{1}{3}\\ x=\dfrac{1}{3}\)