\(22.\left(x+32\right)-5=55.179^0\\ 22.\left(x+32\right)-5=55.1\\ 22.\left(x+32\right)-5=55\\ 22.\left(x+32\right)=55+5\\ 22.\left(x+32\right)=60\\ x+32=60:22\\ x+32=\dfrac{30}{11}\\ x=\dfrac{30}{11}-32\\ x=\dfrac{-322}{11}\)
\(22.\left(x+32\right)-5=55.179^0\)
=>22.(x+32)-5=55.1
=>22.(x+32)-5=55
=>22.(x+32)=55+5
=>22.(x+32)=60
=>x+32=60:22
=>x+32=\(\dfrac{30}{11}\)
=>x=\(\dfrac{30}{11}-32\)
\(=>x=-\dfrac{322}{11}\)
Vậy............
22.(x+32)–5=55.179⁰
`22xx(x+32)-5=55xx1`
`22xx(x+32)-5=55`
`22xx(x+32)=55+5`
`22xx(x+32)=60`
`x+32=60:22`
`x+32=30/11`
`x=30/11-32`
`x=-322/11`
\(22.\left(x+32\right)-5=55.179^0\)
\(22.\left(x+32\right)-5=55.1\)
\(22.\left(x+32\right)-5=55\)
\(22.\left(x+32\right)=55+5\)
\(22.\left(x+32\right)=60\)
\(x+32=60:22\)
\(x+32=\dfrac{30}{11}\)
\(x=\dfrac{30}{11}-32\)
\(x=\dfrac{-322}{11}\)