148-x/25-169-x/23+186-x/4+199-x/19=10.tìm x
Tìm x:
(148-x)/25+(169-x/23+(186-x)/21+(199-x)/10=10
Tìm x,biết
x-10/30 + x-14/43 + x-5/95 + x-148/8 = ?
cho x thỏa mãn 2^225=(2^x)^75 là x=
\(\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x-148}{8}=0\)
Tìm x : \(\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x-148}{8}=0\)0
tìm x
a) ( 152\(\frac{2}{4}\)-148\(\frac{3}{8}\)) : 0,2 = X : 0,3
b) ( (6\(\frac{3}{5}\)-3\(\frac{3}{14}\)) -2,5 ) : ( 21-1,25) = X : 5\(\frac{5}{6}\)
c) (4-\(\frac{3}{4}\)) : ( 2\(\frac{1}{3}\)-1\(\frac{1}{9}\)) = 31. X : ( 45\(\frac{-10}{63}\)-44\(\frac{25}{84}\))
d) \(\frac{2.X+3}{5.X+2}\)=\(\frac{3.X-4}{7}\)
e) \(\frac{3.X-1}{40-5.X}\)=\(\frac{25-3.X}{5.X-34}\)
tìm số tự nhiên x biết rằng 148 chia x đủ 20 con 108 chia cho x thì du 12
tìm x thuộc N*
a)1/1.4 + 1/4.7 +1/7.10 +........+ 1/x.(x+3) = 49/148
Tìm x,y biết 225 - y^2 = 8(x-2018)^2