Question

2¹².3⁵-4⁶.9² phần (2².3)⁶ rút gọn nó

 

Answer 1

\(\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6}=\dfrac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6}=\dfrac{2^{12}.3^4\left(3-1\right)}{2^{12}.3^6}=\dfrac{2}{3^2}=\dfrac{2}{9}\)