2 + x:5 = 6
=>x:5 = 8
=> x= 8:5
=> x= 1 dư 3
2 + x : 5 = 6
x : 5= 6 - 2
x : 5= 4
x = 4. 5
x = 20
2 + x : 5 = 6
x : 5 = 6 - 2
x : 5 = 4
x = 4 x 5
x = 20
\(2+x:5=6\)
\(x:5=4=>x=4\cdot5\)
\(x=20\)
2 + x :5 = 6
=) x : 5 = 6 - 2
=) x : 5 = 4
=) x = 4 x 5
=) x = 20
2 + x : 5 = 6
x : 5 = 6 - 2
x : 5 = 4
x = 4 x 5
x = 20
2+x :5 =6
\(\Rightarrow x:5=6-2\)
\(\Rightarrow\)\(x:5=4\)
\(x=4\cdot\Rightarrow5\)
\(\Rightarrow x=20\)
Ta có :
\(x\div5=6-2\)
\(x\div5=4\)
\(\Rightarrow x=4\times5\)
\(\Rightarrow x=20\)
Code : Breacker
2 + x : 5 = 6
x : 5 = 6 - 2
x : 5 = 4
x = 4 . 5
x = 20
Vậy x = 20 nha bạn !