\((2x-1)^2=121\)
\(\Rightarrow\left(2x-1\right)^2=\left(\pm11\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}2x-1=11\\2x-1=-11\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=12\\2x=-10\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=6\left(tm\right)\\x=-5\left(ktm\right)\end{matrix}\right.\)
Vậy \(x=6\).
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\(\left(2x-1\right)^2=121\\ 2x-1=\sqrt{121}\\ 2x-1=11\\ 2x=12\\ x=\dfrac{12}{2}=6\)
Vậy \(x=6\)
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