\(2^{x-1}=16\)
\(\Leftrightarrow2^{x-1}=2^4\)
\(\Leftrightarrow x-1=4\)
\(\Leftrightarrow x=5\)
Vậy x=5
\(2^{x-1}=16\)
\(2^{x-1}=2^4\)
\(>>x-1=4\)
\(>>x=4+1\)
\(>>x=5\)
Ta có:2x-1=16
2x-1=24
=>x-1=4
=>x=4+1
=>x=5
Vậu x=5
2x-1 =16
2x-1 =24
= > x-1 = 4
x = 4+1
x = 5
\(2^{x-1}=16\)
Mà \(2^4=16\)
\(\Rightarrow x-1=4\)
\(x=4+1\)
\(\Rightarrow x=5\)
2x - 1 = 16
=> 2x - 1 = 24
=> x - 1 = 4
x = 4 - 1
x = 3
Vậy x = 3