1/(x+2000)(x+2001) + 1/(x+2001)(x+2002) +1/(x+2002)(x+2003) +........+ 1/(x+2006)(x+2007)= 7/8
\(\frac{1}{\left(x+2000\right)\left(x+2001\right)}+\frac{1}{\left(x+2001\right)\left(x+2002\right)}+...+\frac{1}{\left(x+2006\right)\left(x+2007\right)}=\frac{7}{8}\)
\(\dfrac{x+1}{2004}+\dfrac{x+2}{2003}=\dfrac{x+3}{2002}+\dfrac{x+4}{2001}\)
giải phương trình sau:
(2-x) /2001 -1 =(1 -x) /2002 - x/2003
Giải phương trình:
a, x-1/2+x-1/4=1-2(x-1)/3.
b,2-x/2001-1=1-x/2002-x/2003
\(\frac{X}{2000}+\frac{X+1}{2001}+\frac{X+2}{2002}+\frac{X+3}{2003}=4\)
\(\frac{x+1}{2004}+\frac{x+2}{2003}=\frac{x+3}{2002}+\frac{x+4}{2001}\)
Giải phương trình : \(\frac{2-x}{2001}-1=\frac{1-x}{2002}-\frac{x}{2003}\).
Giải phương trình : 1/(x+2002)(x+2001) + 1/(x+2001)(x+2002) +...... 1/(x+2006)(x+2007) =7/8
