Question

1:tính

a.b=9! - 8! - 7! . 8^2

b.C=(3.4.2^16)^2 / 11. 2^13 . 4^11 . 16^9

Answer 1

a,9!-8!-7!.8^2

=362880-40320-5040.64

=322560-5040.64

=317520.64

=20321280

b,\(\frac{\left(3.4.2^{16}\right)^2}{11\cdot2^{13}.4^{11}.16^9}=\frac{\left(3^{16}.4^{16}.2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}.\left(2^4\right)^9}=\frac{3^{32}.4^{32}.2^{32}}{11.2^{13}.2^{22}.2^{36}}=\frac{3^{32}.\left(2^2\right)^{32}.2^{32}}{11.2^{71}}=\frac{3^{32}.2^{64}.2^{32}}{11.2^{71}}=\frac{3^{32}.2^{96}}{11.2^{71}}=\frac{3^{32}.2^{71}.2^{25}}{11.2^{71}}=\frac{3^{32}.2^{25}}{11}\)