Question

1.Tính x:

\(1-\left\{5-\frac{4}{9}+x-7\frac{7}{18}\right\}:15\frac{3}{4}=0\)

Answer 1

mik nhầm nha mn

\(1-\left\{5\frac{4}{9}+x-7\frac{7}{18}\right\}:15\frac{3}{4}=0\)

Answer 2

           Bài làm :

Ta có :

\(...\)

\(\left\{5-\frac{4}{9}+x-7\frac{7}{18}\right\}\div15\frac{3}{4}=1\)

\(5-\frac{4}{9}+x-7\frac{7}{18}=15\frac{3}{4}\)

\(x-\frac{17}{6}=15\frac{3}{4}\)

\(x=15\frac{3}{4}+\frac{17}{6}=\frac{223}{12}\)

Vậy x=223/12

Answer 3

           Bài làm khi sửa lại đề :

Ta có :

\(1-\left\{5\frac{4}{9}+x-7\frac{7}{18}\right\}\div15\frac{3}{4}=0\)

\(\left\{5\frac{4}{9}+x-7\frac{7}{18}\right\}\div15\frac{3}{4}=1\)

\(x-\frac{35}{18}=15\frac{3}{4}\)

\(x=15\frac{3}{4}+\frac{35}{18}=\frac{637}{36}\)

Vậy x=637/36