\(a, 3\left(2-x\right)+5\left(x-6\right)=-98\Leftrightarrow6-3x+5x-30=-98\)
\(\Leftrightarrow2x=-74\)
\(\Leftrightarrow x=-37\)
\(b,\)\(\Leftrightarrow x^2+1=0\left(v\text{ô} nghi\text{ệm}\right)ho\text{ặc} 49-x^2=0\)
\(\Leftrightarrow x=7 ho\text{ặc} x=-7\)
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a)3(2-x)+5(x-6)=-98
6-3x+5x-30=98
-3x+5x =98+30-6
x(-3+5) =122
x.2 =122
x =122:2=61
b)(x^2+1)(49-x^2)=0
=>x2+1=0 hoặc 49-x2=0
x2=-1(vô lí)hoặc x2 =49
=>x=7
a)3(2-x)+5(x-6)=-98
6-3x+5x-30=-98
-3x+5x =-98+30-6
x(-3+5) =-74
x.2 =-74
x =122:2=-37
b)(x^2+1)(49-x^2)=0
=>x2+1=0 hoặc 49-x2=0
x2=-1(vô lí)hoặc x2 =49
=>x=7