Ta có: \(\frac{1}{101}>\frac{1}{150}\)
\(\frac{1}{102}>\frac{1}{150}\)
.........................
\(\frac{1}{150}=\frac{1}{150}\)
\(\Rightarrow\frac{1}{101}+\frac{1}{102}+...+\frac{1}{150}>\frac{1}{150}+\frac{1}{150}+...+\frac{1}{150}=50.\frac{1}{150}=\frac{1}{3}\)(1)
Ta có:
\(\frac{1}{151}>\frac{1}{200}\)
\(\frac{1}{152}>\frac{1}{200}\)
...........................
\(\frac{1}{200}=\frac{1}{200}\)
\(\Rightarrow\frac{1}{151}+\frac{1}{152}+...+\frac{1}{200}>\frac{1}{200}+\frac{1}{200}+...+\frac{1}{200}=50.\frac{1}{200}=\frac{1}{4}\)(2)
Từ (1) và (2) ta có:
\(\frac{1}{101}+\frac{1}{102}+...+\frac{1}{150}+\frac{1}{151}+\frac{1}{152}+...+\frac{1}{200}>\frac{1}{3}+\frac{1}{4}=\frac{4}{12}+\frac{3}{12}=\frac{7}{12}\)
đpcm