Question

1+sin2x=2(sin^4x+cos^4x)

Answer 1

tanx=3cotx

đk:\(\left\{{}\begin{matrix}sinX#0\\coxX#0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}X#k\pi\\X#\frac{\pi}{2}+k\pi\end{matrix}\right.\left(k\in Z\right)\)