Câu 1:
PTHH: \(CuO+2HNO_3\rightarrow Cu\left(NO_3\right)_2+H_2O\)
\(3Cu+8HNO_{3\left(ddloãng\right)}\rightarrow3Cu\left(NO_3\right)_2+2NO+4H_2O\)
Ta có: \(n_{NO}=\frac{3,36}{22,4}=0,15\left(mol\right)\) \(\Rightarrow n_{Cu}=0,225\left(mol\right)\)
\(\Rightarrow m_{Cu}=0,225\cdot64=14,4\left(g\right)\) \(\Rightarrow m_{CuO}=0,6\left(g\right)\) \(\Rightarrow\%m_{CuO}=\frac{0,6}{15}\cdot100\%=4\%\)
Câu 2: Dùng dd NaOH dư để hấp thụ hết các khí trừ N2