Tu (x+3)/(y+5)=(x+5)/(y+7) suy ra xy+3y+7x+21=xy+5y+5x+25 \(\Rightarrow\)3y+7x=5y+5x+4\(\Rightarrow\)2x=2y+4=2(y+2)\(\Rightarrow\)x=y+2\(\Rightarrow\)x-y=2.\(\left(2x\right)^3=y^3\Rightarrow2x=y\Rightarrow\frac{x}{y}=\frac{x}{2x}=\frac{1}{2}\)
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