Question

\(1\frac{1}{3}x-\frac{1}{3}=\left(2x-1\right):\left(1-\frac{2}{5}\right)tìmx\)

Answer 1

Từ đề bài ta có:

4/3x - 1/3 = (2x-1) : 3/5 

=> 4/3x -1/3 = (2x-1) * 5/3

=> 4/3x -1/3= 10/3x - 5/3

Chuyển vế đổi dấu

Ta được:

=> -2x = -4/3

=> x= 2/3

Vậy x= 2/3

 

Answer 2

\(1\frac{1}{3}x=\left(2x-1\right):\left(1-\frac{2}{5}\right)\)

\(\frac{4}{3}x=\left(2x-1\right):\left(\frac{3}{5}\right)\)

\(\frac{4}{3}x.\frac{3}{5}=\left(2x-1\right)\)

\(\frac{4}{5}x=\left(2x-1\right)\)

\(x=\left(2x-1\right):\frac{4}{5}\)

\(x=\left(2x-1\right).\frac{5}{4}\)

\(x=2x.\frac{5}{4}-1.\frac{5}{4}\)

\(x=\)\(2x.\frac{5}{4}-\frac{5}{4}\)

\(x=2.\frac{5}{4}.x-\frac{5}{4}\)

\(x=\left(\frac{5}{2}.x\right)-\frac{5}{4}\)

\(x=\frac{5}{2}-\frac{5}{4}.x-\frac{5}{4}\)

\(x=\frac{5}{4}.x-\frac{5}{4}\)

\(x=x\left(\frac{5}{4}-\frac{5}{4}\right)\)

\(x=x.0\)

\(=>x=0\)