\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{13}{12}:3\)
tính
Rút gọn các biểu thức sau:
1.\(\frac{13}{15}-0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
1\(\frac{13}{15}\)*0,75-(\(\frac{104}{195}\)+25%)*\(\frac{24}{47}\)-\(3\frac{12}{13}\)/3
Tính :
\(A=\frac{28}{15}.\left(\frac{1}{2}\right)^2.3+\left(\frac{8}{15}-\frac{79}{60}\right).\frac{24}{47}\)
\(B=\frac{75}{100}.\frac{28}{15}-\left(\frac{104}{195}+\frac{25}{100}\right).\frac{24}{47}-\frac{51}{13}.\frac{1}{3}\)
Ai làm xong mk k nha!!!
\(1\frac{13}{15}.0,75-\left(\frac{8}{15}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
Tìm x
\(4\frac{1}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\le x\le\frac{2}{3}.\left(\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\right)\)
1\(\frac{13}{15}\). 0.75 - (\(\frac{104}{195}\)+ 25%) . \(\frac{24}{47}\)- 3\(\frac{12}{13}\): 3
Câu 1 Tim số nguyên x, biet rằng
\(4\frac{1}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\le\times\le\frac{2}{3}.\left(\frac{1}{2}-\frac{1}{2}-\frac{3}{4}\right)\)
Câu 2 : Tính
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
Câu 3 ; Tìm x Biet
\(\left(\frac{1}{12}+3\frac{1}{6}-30,75\right).\times-8=\left(\frac{3}{5}+0,415+\frac{1}{200}\right):0,01\)
Câu 4 : So Sánh \(A=\frac{10^8+2}{10^8-1}\);
Tính
\(1\frac{13}{15}.0,75-\left(\frac{8}{15}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
Tìm x
\(4\frac{1}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\le x\le\frac{2}{3}.\left(\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\right)\)
GIẢI CỤ THỂ GIÚP MK VỚI !!
\(1\dfrac{13}{15}\).0,75-(\(\dfrac{104}{195}\)+25%).\(\dfrac{24}{47}\)-\(3\dfrac{12}{13}\):3
