1ab+36=ab1
⇔100+10a+b+36=100a+10b+1
⇔100a+10b−10a−b=136−1
⇔90a+9b=135
⇔9(10a+b)=135
⇒ab=135:9=15
1ab+36=ab1
100+10a+b+36=100a+10b+1100+10a+b+36=100a+10b+1
135=100a−10a+10b−b135=100a−10a+10b−b
135=90a+9b135=90a+9b
135=9(10a+b)135=9(10a+b)
10+b=1510+b=15
ab=15
Vậy thay vào ta có : 115+36=151
Ta có :
1ab + 36 = ab1
\(\Rightarrow\) 100 + ab + 36 = 10ab + 1
\(\Rightarrow\) 10ab - ab = 100 +36 - 1
\(\Rightarrow\) 9ab = 135
\(\Rightarrow\) ab = 135 \(\div\)9
\(\Rightarrow\) ab = 15
Vậy số ab cần tìm là 15