\(\frac{1}{9}=\frac{x+5}{27}\)
=> 9(x + 5) = 27
=> 9x + 45 = 27
=> 9x = 27 - 45
=> 9x = -18
=> x = -18 : 9
=> x = -2
\(x=\frac{1}{9}-\frac{5}{27}=\frac{3}{27}-\frac{5}{27}=\frac{-2}{27}\)
\(\frac{1}{9}=x+\frac{5}{27}\)
\(x+\frac{5}{27}=\frac{1}{9}\)
\(x=\frac{1}{9}-\frac{5}{27}\)
\(x=\frac{1}{9}+\frac{-5}{27}\)
\(x=\frac{3}{27}+\frac{-5}{27}\)
\(x=\frac{-2}{27}\)
Vậy \(x=\frac{-2}{27}\)
ta có \(\frac{x+5}{27}=\frac{1}{9}\)
\(\Rightarrow\)\(9.\left(x+5\right)=27\)
\(\Rightarrow\)\(9x+45=27\)
\(\Rightarrow\)\(9x=-18\)
\(\Rightarrow\)\(x=-2\)
vậy \(x=-2\)