Question

(1/9)^x = (1/27)^22

(4/9)^x  = (8/27)^6

                      Tìm X

Answer 1

a) \(\left(\frac{1}{9}\right)^x=\left(\frac{1}{27}\right)^{22}\)

\(\left[\left(\frac{1}{3}\right)^2\right]^x=\left[\left(\frac{1}{3}\right)^3\right]^{22}\)

\(\left(\frac{1}{3}\right)^{2\cdot x}=\left(\frac{1}{3}\right)^{66}\)

\(\Rightarrow2\cdot x=66\)

\(x=66\div2\)

\(x=33\)
Vậy x = 33
b) \(\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^6\)

\(\left[\left(\frac{2}{3}\right)^2\right]^x=\left[\left(\frac{2}{3}^3\right)\right]^6\)

\(\left(\frac{2}{3}\right)^{2\cdot x}=\left(\frac{2}{3}\right)^{18}\)

\(\Rightarrow2\cdot x=18\)

\(x=18\div2\)

\(x=9\)

Vậy x = 9