\(1999\cdot2002-\dfrac{1}{1998}+1999\cdot2000\cdot\dfrac{7}{5}\)
\(=1999\cdot\left(2002-2000\right)-\dfrac{1}{1998}\cdot\dfrac{7}{5}\)
\(=1999\cdot2-\dfrac{1}{1998}\cdot\dfrac{7}{5}\)
\(=3998-\dfrac{7}{9990}\)
\(=3997\dfrac{999299}{1000000}\)
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