Question

16x²+22x-3=0

Answer 1

pt <=> (16x^2-24x)+(2x-3) = 0

<=> (2x-3).(8x+1) = 0

<=> 2x-3=0 hoặc 8x+1=0

<=> x=3/2 hoặc x=-1/8

Vậy ..............

Answer 2

Theo bài ra ta có:\(16.x^2+22x-3=0\)

\(\Rightarrow\left(16x+22\right)x=3=1.3=3.1=\left(-1\right).\left(-3\right)=\left(-3\right).\left(-1\right)\)

Tự kẻ bẳng nha

Answer 3

\(16x^2+22x-3=0\)

\(\Leftrightarrow16x\left(x-\frac{1}{8}\right)+24\left(x-\frac{1}{8}\right)=0\)

\(\Leftrightarrow\left(x-\frac{1}{8}\right)\left(16x+24\right)=0\)

\(\Leftrightarrow8\left(x-\frac{1}{8}\right)\left(2x+3\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-\frac{1}{8}=0\\2x+3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{8}\\x=-\frac{3}{2}\end{cases}}}\)

Answer 4

uk mk bị nhầm trừ thành cộng nha !