Câu hỏi của nguyễn phương ngân

Question

1/5*8+1/8*11+...+1/x*(x+3)=101/1540

soyeon_Tiểu bàng giải · Accepted Answer

$\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{x.\left(x+3\right)}=\frac{101}{1540}$ $3.\left(\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{x.\left(x+3\right)}\right)=3.\frac{101}{1540}$$\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{x.\left(x+3\right)}=\frac{303}{1540}$$\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{303}{1540}$$\frac{1}{5}-\frac{1}{x+3}=\frac{303}{1540}$$\frac{1}{x+3}=\frac{1}{5}-\frac{303}{1540}$$\frac{1}{x+3}=\frac{308}{1540}-\frac{303}{1540}$$\frac{1}{x+3}=\frac{5}{1540}=\frac{1}{308}$=> x + 3 = 308=> x = 308 - 3=> x = 305Vậy x = 305Câu trả lời: $\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{x.\left(x+3\right)}=\frac{101}{1540}$ $3.\left(\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{x.\left(x+3\right)}\right)=3.\frac{101}{1540}$$\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{x.\left(x+3\right)}=\frac{303}{1540}$$\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{303}{1540}$$\frac{1}{5}-\frac{1}{x+3}=\frac{303}{1540}$$\frac{1}{x+3}=\frac{1}{5}-\frac{303}{1540}$$\frac{1}{x+3}=\frac{308}{1540}-\frac{303}{1540}$$\frac{1}{x+3}=\frac{5}{1540}=\frac{1}{308}$=> x + 3 = 308=> x = 308 - 3=> x = 305Vậy x = 305

Edogawa Conan · Answer

$\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{x.\left(x+3\right)}=\frac{101}{1540}$$3.\left(\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{x.\left(x+3\right)}\right)=3.\frac{101}{1540}$$\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{303}{1540}$$\frac{1}{5}-\frac{1}{x+3}=\frac{303}{1540}$$\frac{1}{x+3}=\frac{1}{5}-\frac{303}{1540}$$\frac{1}{x+3}=\frac{5}{1540}=\frac{1}{308}$=> x + 3 = 308=> x = 308 - 3=> x = 305Vậy x = 305Câu trả lời: $\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{x.\left(x+3\right)}=\frac{101}{1540}$$3.\left(\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{x.\left(x+3\right)}\right)=3.\frac{101}{1540}$$\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{303}{1540}$$\frac{1}{5}-\frac{1}{x+3}=\frac{303}{1540}$$\frac{1}{x+3}=\frac{1}{5}-\frac{303}{1540}$$\frac{1}{x+3}=\frac{5}{1540}=\frac{1}{308}$=> x + 3 = 308=> x = 308 - 3=> x = 305Vậy x = 305

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