14/10 .15/19 -(4/5 + 2/3):2 +1/5
=7/5 .15/19 -(12/15 +10/15):11/5
=7/5.15/19 -22/15:11/5
=7/57-2/3
=7/57+(-38/57)
= -31/57
\(\frac{15}{49}\) mà
bt rùi hỏi làm j
\(\frac{15}{49}-\left(\frac{4}{5}+\frac{2}{3}\right)\div2\frac{1}{5}\)
= \(\frac{15}{49}-\left(\frac{12}{15}+\frac{10}{15}\right)\div\frac{11}{5}\)
= \(\frac{15}{49}-\frac{22}{15}\times\frac{5}{11}\)
= \(\frac{15}{49}-\frac{2}{3}\)
= \(\frac{45}{147}-\frac{98}{147}\)
= \(\frac{-53}{147}\)
7/5.15/49-(4/5+2/3):11/5
7/5.15/49-22/15:11/5
3/7-22/5:115
3/7-22/5.5/11
3/7-2/1
-11/7
