Question

-12x^2 (5x+4) +6x * (10x^2+8x)-2x(x+1)= -4 tìm x

Answer 1

-12x^2 (5x+4) +6x * (10x^2+8x)-2x(x+1)= -4

\(VT=-2x^2-2x\)

\(\Leftrightarrow-2x^2-2x=-4\)

\(\Leftrightarrow-2x^2-2x+4=0\)

\(\Leftrightarrow-2\left(x^2+x-2\right)=0\)

\(\Leftrightarrow x^2+x-2=0\)

\(\Leftrightarrow x^2-x+2x-2=0\)

\(\Leftrightarrow x\left(x-1\right)+2\left(x-1\right)=0\)

\(\Leftrightarrow\left(x+2\right)\left(x-1\right)=0\)

\(\Leftrightarrow x=-2\)hoặc\(x=1\)