Question

(1+2+3+4+5+6+...+999+1000)×(0.75×0.4−\(\dfrac{3}{4}\)×0.4)

Answer 1

\(=\left(1+2+3+...+1000\right)\times\left[\left(0,75-\dfrac{3}{4}\right)\cdot0,4\right]\)

\(=\left(1+2+3+...+1000\right)\times0=0\)