(1.2 + 2.3 + 3.4 +...+ 98.99) . \(\dfrac{x}{26950}\) = \(\dfrac{90}{7}\):1,5
Áp dụng ct: 1.2 + 2.3+ 3.4 +....+n.(n+1) = n(n+1)(n+2):3
Ta có:
\(\dfrac{98.99.100}{3}\).\(\dfrac{x}{26950}\) = \(\dfrac{90}{7}\):\(\dfrac{3}{2}\)
12\(x\) = \(\dfrac{60}{7}\)
\(x\) = \(\dfrac{60}{7}\): 12
\(x\) = \(\dfrac{5}{7}\)