Đặt A = 1.2 + 2.3 + 3.4 + 4.5 + ... + 99.100
3A = 1.2.(3-0) + 2.3.(4-1) + 3.4.(5-2) + 4.5.(6-3) + ... + 99.100.(101-98)
3A = 1.2.3 - 0.1.2 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + 4.5.6 - 3.4.5 + ... + 99.100.101 - 98.99.100
3A = 99.100.101
A = 33.100.101
A = 333300
A=1.2+2.3+3.4+...+99.100
3A=1.2.3+2.3.3+3.4.3+...+99.100.3=1.2(3-0)+2.3(4-1)+3.4(5-2)+...+99.100(101-98)=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-99.100.98=99.100.101
Vậy A= 99.101.100/3
dung xich ma \sum_1^99 x(x+1) = 333300
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Đặt A = 1.2 + 2.3 + 3.4 + 4.5 + ... + 99.100
3A = 1.2.(3-0) + 2.3.(4-1) + 3.4.(5-2) + 4.5.(6-3) + ... + 99.100.(101-98)
3A = 1.2.3 - 0.1.2 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + 4.5.6 - 3.4.5 + ... + 99.100.101 - 98.99.100
3A = 99.100.101
A = 33.100.101
A = 333300