\(\dfrac{1}{2}x-\left(\dfrac{4}{7}\right)^2=\left(-\dfrac{4}{7}\right)^2\)
\(\dfrac{1}{2}x-\dfrac{16}{49}=\dfrac{16}{49}\)
\(\dfrac{1}{2}x=\dfrac{16}{49}+\dfrac{16}{49}\)
\(\dfrac{1}{2}x=\dfrac{32}{49}\)
\(x=\dfrac{32}{49}:\dfrac{1}{2}\)
Vậy \(x=\dfrac{64}{49}\)
\(< =>\dfrac{1}{2}x-\dfrac{16}{49}=\dfrac{16}{49}< =>\dfrac{1}{2}X=0< =>x=0\)