\(\frac{1}{2}+\frac{3}{10}=\frac{1}{2}z\)
\(\Rightarrow\frac{1}{2}-\frac{1}{2}z=\frac{3}{10}\)
\(\Rightarrow\frac{1}{2}(z-1)=\frac{1}{2}.\frac{3}{5}\)
\(\Rightarrow\frac{1}{2}(z-1)-\frac{1}{2}.\frac{3}{5}=0\)
\(\frac{1}{2}.[(z-1)-\frac{3}{5}]=0\)
\(\Rightarrow z-(1+\frac{3}{5})=\frac{-1}{2}\)
\(\Rightarrow z-\frac{8}{5}=\frac{-1}{2}\)
\(\Rightarrow z=\frac{-1}{2}-\frac{8}{5}\)
\(\Rightarrow z=\frac{-11}{10}\)
\(\text{Làm lại : Bài trên mình làm sai }\)\(\frac{1}{2}+\frac{3}{10}=\frac{1}{2}.z\)
\(\frac{1}{2}-\frac{1}{2}.z=\frac{-3}{10}\)
\(\frac{1}{2}.\left(1-z\right)=\frac{-3}{10}\)
\(1-z=\frac{-3}{10}:\frac{1}{2}\)
\(1-z=\frac{-3}{5}\)
\(z=1-\frac{-3}{5}\)
\(z=\frac{8}{5}\)