\(\left(\sqrt{12}+\sqrt{27}-\sqrt{48}\right)\sqrt{3}\)
\(=\left(2\sqrt{3}+3\sqrt{3}-4\sqrt{3}\right)\sqrt{3}\)
\(=\sqrt{3}\cdot\sqrt{3}=3\)
4√27-2√48 +3√12-√75
\(\sqrt{12}+4\sqrt{27}-3\sqrt{48}\)
Rút gọn các biểu thức sau a)√27-✓12+✓48-5✓3 b)5✓18-✓5+✓20+✓1 2 C)✓25:✓16=✓36:✓9 D)✓12+✓27-5✓3 E)2✓3-✓75+2✓12
Rút gọn: \(2\sqrt{40\sqrt{12}}+3\sqrt{5\sqrt{48}}-2\sqrt{\sqrt{75}}-4\sqrt{15\sqrt{27}}\)
a)5\(\sqrt{27}\)+3\(\sqrt{48}\)-2\(\sqrt{12}\)-6\(\sqrt{3}\)
b)\(\dfrac{3}{2+\sqrt{3}}\)+\(\dfrac{13}{4-\sqrt{3}}\)+\(\dfrac{6}{\sqrt{3}}\)
căn bậc 2 27+48-108-12
căn bậc 2 của 27+48-108-12
rút gọn biểu thức
A=2\(\sqrt{27}\)+5\(\sqrt{12}\)-3\(\sqrt{48}\)
B=\(\sqrt{147}\)+\(\sqrt{75}\)-4\(\sqrt{27}\)
C=3\(\sqrt{2}\)(4-\(\sqrt{2}\))+3(1-2\(\sqrt{2}\))2
D=2\(\sqrt{5}\)-\(\sqrt{125}\)-\(\sqrt{80}\)+\(\sqrt{605}\)
\(\left(5\sqrt{48}+4\sqrt{27}-2\sqrt{12}\right):\sqrt{3}\)= ?
