1/2 - (1/3 + 1/4) < x < 1/48 - (1/16 - 1/6)
=> 1/2-7/12
=-1/2
1/48 - (-5/48)
=1/8
=>-1/2<x<1/8
=>x=
tự suy ra nhé
$\dfrac{1}{2}$ - ($\dfrac{1}{3}$ + $\dfrac{1}{4}$) < x < $\dfrac{1}{48}$ - ($\dfrac{1}{16}$ - $\dfrac{1}{6}$)
$\dfrac{1}{2}$ - $\dfrac{7}{12}$ < x < $\dfrac{1}{48}$ - $\dfrac{-5}{48}$
$\dfrac{-1}{12}$ < x < $\dfrac{1}{8}$
=> x \(\in\) ($\dfrac{-1}{12}$; $\dfrac{1}{8}$).
\(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{1}{4}\right)< x< \dfrac{1}{48}-\left(\dfrac{1}{16}-\dfrac{1}{6}\right)\)
\(\dfrac{6}{12}-\left(\dfrac{4}{12}+\dfrac{3}{12}\right)< x< \dfrac{1}{48}-\left(\dfrac{3}{48}-\dfrac{8}{48}\right)\)
\(\dfrac{6}{12}-\dfrac{7}{12}< x< \dfrac{1}{48}-\left(-\dfrac{5}{48}\right)\)
\(-\dfrac{1}{12}< x< \dfrac{1}{8}\)
`1/2 - (1/3 + 1/4) < x < 1/48 - (1/16 - 1/6)`
`<=> 1/2 - 1/3 - 1/4 < x < 1/48 - 1/16 + 1/6`
`<=> 6/12 - 4/12 - 3/12 < x < 1/48 - 3/48 + 8/48`
`<=> -1/12 < x < 6/48 = 1/8 `