\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{x\left(x+1\right)}=\frac{996}{997}\)
\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{996}{997}\)
\(1-\frac{1}{x+1}=\frac{996}{997}\)
\(\frac{1}{x+1}=1-\frac{996}{997}=\frac{1}{997}\)
\(\Rightarrow x+1=997\Rightarrow x=996\)
Vậy \(x=996\)
Tim x biết 1\1x2+1\2*3 +1\3*4+----+1\**(×+1)=996\997
\(\frac{1}{1x2}\)+\(\frac{1}{2x3}\)+\(\frac{1}{3x4}\)+...+\(\frac{1}{yx\left(y+1\right)}\)=\(\frac{996}{997}\)
Ai nhanh mình tick nè !
tim:1/1*2+1/2*3+1/3*4+...+1/x*(x+1)=996/997
Tìm X:
1:1x2+1:2x3+1:3x4+....+1: (X-1)x X=15:16
Chú ý : dấu chia là phân số
tính tổng: 1/1x2 + 1/2x3 + 1/ 3x4 +...+ 1/98 x 99 + 1/99 x 100
1/(1x2)+1/(2x3)+1/(3x4)...+1/xx(x+1)
tìm x
1/ 1x2 + 1/2x3 +1/3x4 + ....+ 1/xnhân(x+1 ) = 2013/2014
1/1x2 +1/2x3+1/3x4+1/4 x 5......... 1/999x1000+1
Tìm x biết:
\(\dfrac{x}{x+1}=\dfrac{1}{1x2}+\dfrac{1}{2x3}+\dfrac{1}{3x4}+...+\dfrac{1}{31x32}\)
Trả lời nhanh giúp mìn nhé
