(1+1/2) x (1+1/3) x ..... x ( 1 x 1/2005)
(1+1/2)x(1+1/3)x...(1+1/2005)
a) tính nhanh
( 1 + \(\dfrac{1}{2}\) ) x ( 1 + \(\dfrac{1}{3}\) ) x ..... x ( 1 + \(\dfrac{1}{2005}\) )
b) tính bằng cách thuận tiện
\(\dfrac{2}{3}\) x \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) x \(\dfrac{1}{2}\)
Tính nhanh : a [ 1 + 1 /2 ] x [ 1 + 1 / 3 ] x [ 1 + 1 / 4 ] x .... x [ 1 + 1 / 2005 ]
( 2006 x 2005 + 2005 + 2004 ) x (1 + \(\frac{1}{2}:\frac{3}{2}-\frac{3}{4}\)) = ?
Tính:(1+1/2005) x (1+ 1/2006) x (1+ 1/2007) x (1+ 1/2008) x (1 + 1/2009)
Tính kết quả sau: { 2003 x 2004+ 2004 x 2005 }x { 2005 :1 -1 x2005}
Tính kết quả sau:
[ 2003 x 2004 + 2004 x 2005} x{ 2005:1 - 1 x2005}
Tính nhanh :
( 1 - 1/99 ) x ( 1- 1/100 ) x ... x ( 1- 2005 )
