(\(\dfrac{1}{1.2.3}\)+\(\dfrac{1}{2.3.4}\)+...+\(\dfrac{1}{8.9.10}\)).x=\(\dfrac{23}{45}\)
tìm so tu nhien x biet (1/1.2.3 + 1/2.3.4+...+ 1/8.9.10).x=23/45
tim so tu nhien x biet (1/1.2.3 + 1/2.3.4 +...+ 1/8.9.10).x =23/45
tìm x biết
(1/1.2.3+1/2.3.4+1/3.4.5+...+1/8.9.10)x=23/45
Tìm x
[1/1.2.3 +1/2.3.4 +...+1/8.9.10].x =23/45
Tìm số tự nhiên x biết
(1/1.2.3 + 1/2.3.4 + 1/ 3.4.5 +...+ 1/ 8.9.10) x = 23/45
(1/1.2.3+1/2.3.4+..............+1/8.9.10).x=23/45
nhờ các bn giải giúp tớ vs. Cảm ơn
tìm x :(1/1.2.3 + 1/2.3.4 + 1/ 3.4.5 +...+ 1/ 8.9.10) x = 23/45
Tim x biet
\(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}\right).x=\frac{23}{45}\)
