Question

1+1/2+1/3+1/4+...+1/2020

Answer 1

\(1+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{2020}\)

\(=\dfrac{1}{1+2+3+...+2020}\)

\(=\dfrac{1}{\left(2020-1\right)+1}\)

\(=\dfrac{1}{2020}\)