\(\left(1+\frac{1}{1.3}\right).\left(1+\frac{1}{2.4}\right)......\left(1+\frac{1}{2016.2018}\right)\)
\(=\left(\frac{1.3}{1.3}+\frac{1}{1.3}\right).\left(\frac{2.4}{2.4}+\frac{1}{2.4}\right).....\left(\frac{2016.2018}{2016.2018}+\frac{1}{2016.2018}\right)\)
\(=\left(\frac{1.3+1}{1.3}\right).\left(\frac{2.4+1}{2.4}\right).....\left(\frac{2016.2018+1}{2016.2018}\right)\)
\(=\frac{4}{1.3}.\frac{9}{2.4}.....\frac{4068289}{2016.2018}=\frac{2^2}{1.3}.\frac{3^2}{2.4}....\frac{2017^2}{2016.2018}\)
\(=\frac{2^2.3^2.....2017^2}{1.3.2.4.....2016.2018}=\frac{2.2.3.3.4.4...2017.2017}{1.3.2.4.....2016.2018}=\frac{\left(2.3.4.....2017\right).\left(2.3.4..2017\right)}{\left(1.2....2016\right).\left(3.4....2018\right)}\)
\(=\frac{2017.2}{1.2018}=\frac{4034}{2018}\)
bạn trả lời sai toẹt phải làm như này mới đúng
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