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(1/100-12).(1/100-1/22).(1/100-1/32)....(1/100-1/202)

Nguyễn Thị Thương Hoài · Accepted Answer

A = ($\dfrac{1}{100}$ - 12).($\dfrac{1}{100}$ - $\dfrac{1}{2^2}$).($\dfrac{1}{100}$ - $\dfrac{1}{3^2}$)...($\dfrac{1}{100}$ - $\dfrac{1}{20^2}$)

A = ($\dfrac{1}{10^2}$ - 12).($\dfrac{1}{10^2}$ - $\dfrac{1}{2^2}$).($\dfrac{1}{10^2}$ - $\dfrac{1}{3^2}$)..($\dfrac{1}{10^2}$ - $\dfrac{1}{10^2}$)....($\dfrac{1}{10^2}$ - $\dfrac{1}{20^2}$)

A = ($\dfrac{1}{10^2}$ - 12).($\dfrac{1}{10^2}$ - $\dfrac{1}{2^2}$).($\dfrac{1}{10^2}$ - $\dfrac{1}{3^2}$)...0.($\dfrac{1}{10^2}$ - $\dfrac{1}{20^2}$)

A = 0Câu trả lời: A = ($\dfrac{1}{100}$ - 12).($\dfrac{1}{100}$ - $\dfrac{1}{2^2}$).($\dfrac{1}{100}$ - $\dfrac{1}{3^2}$)...($\dfrac{1}{100}$ - $\dfrac{1}{20^2}$)

A = ($\dfrac{1}{10^2}$ - 12).($\dfrac{1}{10^2}$ - $\dfrac{1}{2^2}$).($\dfrac{1}{10^2}$ - $\dfrac{1}{3^2}$)..($\dfrac{1}{10^2}$ - $\dfrac{1}{10^2}$)....($\dfrac{1}{10^2}$ - $\dfrac{1}{20^2}$)

A = ($\dfrac{1}{10^2}$ - 12).($\dfrac{1}{10^2}$ - $\dfrac{1}{2^2}$).($\dfrac{1}{10^2}$ - $\dfrac{1}{3^2}$)...0.($\dfrac{1}{10^2}$ - $\dfrac{1}{20^2}$)

A = 0

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