\(\text{9 : ( x + 1 ) = 100-19 9 : ( x + 1 ) = 81 x + 1 = 9 : 81 x + 1 = 1/9 }\)
= 9 : ( x + 1 ) = 100-19
9 : ( x + 1 ) = 81
x + 1 = 9 : 81
x + 1 = 1/9
100 - 9:(x+1) = 19
=> 9:(x+1) = 81
=> x + 1 = \(\frac{1}{9}\)
=> x = \(\frac{1}{9}-1\)
=> x = \(-\frac{8}{9}\)
\(100-9:\left(x+1\right)=19\)
\(91:\left(x+1\right)=19\)
\(x+1=91:19\)
\(x+1=\frac{91}{19}\)
\(x=\frac{91}{19}-1\)
\(x=\frac{72}{19}\)
Các bn mỗi bn 1 câu tl thì mk bik chọn cái nào h
100 - 9 : ( x - 1) = 19
=> 9 : ( x - 1 ) = 81
=> x -1 = 1/9
=> x = 1/9 + 1
=> x = 10/9
100 - 9 : ( x + 1)= 19
9 : ( x + 1 ) = 100 - 19
9 : ( x + 1 ) = 81
x + 1 = 9 : 81
x + 1 = \(\frac{1}{9}\)
Cảm ơn mmoij người rất nhìu ppp mk đi lm đây
Mình làm sai cho mình sửa lại hen :
\(100-9:\left(x+1\right)=19\)
\(9:\left(x+1\right)=100-19\)
\(9:\left(x+1\right)=81\)
\(x+1=9:81\)
\(x+1=\frac{1}{9}\)
\(x=\frac{1}{9}-1\)
\(x=\frac{8}{9}\)
100 - 9 : ( x + 1 ) = 19
9 : ( x + 1) =100-19
9 : ( x + 1 ) =81
( x + 1 )= 9 : 81
\(x+1=\frac{1}{9}\)
\(x=\frac{1}{9}-1\)
\(x=-\frac{8}{9}\)
T mk nhé bạn ^...^ ^_^
100 - 9 : ( x + 1 ) =19
9 : ( x + 1 ) = 100 - 19
9 : ( x + 1 ) = 81
x +1 = 9 : 81
x+1 = 1/9
x = -8/9
x =1 và 1/9
\(100-9:\left(x+1\right)=19\)
\(9:\left(x+1\right)=100-19\)
\(9:\left(x+1\right)=81\)
\(\left(x+1\right)=9:81\)
\(x+1=\frac{1}{9}\)
\(x=\frac{1}{9}-1\)
\(x=\frac{1}{9}-\frac{9}{9}\)
\(x=\frac{-8}{9}\)