\(\frac{3}{2}+\frac{4}{5}=\frac{15}{10}+\frac{8}{10}=\frac{23}{10}\)
\(\frac{2}{5}:\frac{7}{5}=\frac{2}{5}x\frac{5}{7}=\frac{2}{7}\)
\(\frac{2}{3}+\frac{2}{5}-\frac{1}{3}=\frac{16}{15}-\frac{1}{3}=\frac{11}{15}\)
\(\frac{4}{9}x\frac{3}{2}:\frac{2}{3}=\frac{2}{3}:\frac{2}{3}=1\)
\(\frac{3}{2}\)+\(\frac{4}{5}\)=\(\frac{15}{10}+\frac{20}{10}=\frac{35}{10}=\frac{7}{2}\)
\(\frac{2}{5}:\frac{7}{5}=\frac{2}{5}x\frac{5}{7}\)\(=\frac{2}{7}\)
\(\frac{3}{2}\)+ \(\frac{4}{5}\) = \(\frac{15}{10}\) + \(\frac{8}{10}\) = \(\frac{23}{10}\)
\(\frac{2}{5}\) : \(\frac{7}{5}\) = \(\frac{2}{5}\) x \(\frac{5}{7}\) = \(\frac{2}{7}\)
\(\frac{2}{3}\)+ \(\frac{2}{5}\) - \(\frac{1}{3}\)= \(\frac{10}{15}\) + \(\frac{6}{15}\) - \(\frac{5}{15}\) = \(\frac{11}{15}\)
\(\frac{4}{9}\) x \(\frac{3}{2}\) : \(\frac{2}{3}\) = \(\frac{2}{3}\) : \(\frac{2}{3}\)= 1