\(3x=y\)=> \(\frac{x}{1}=\frac{y}{3}\)
hay \(\frac{x}{4}=\frac{y}{12}\)
\(5y=4z\)=> \(\frac{y}{4}=\frac{z}{5}\)
hay \(\frac{y}{12}=\frac{z}{15}\)
suy ra: \(\frac{x}{4}=\frac{y}{12}=\frac{z}{15}\)
đến đây bạn ADTCDTSBN nhé
tìm x, y, z khi:
a,cho 3x=y , 5y=4z và 6x+7y+8z = 456
b, \(\frac{4-z}{1}=\frac{y+z}{2}=\frac{x+y}{3}=\frac{y+8}{5}\)
c, ( x - \(\frac{1}{5}\)) ^2004+ ( y+0.4) ^ 100 + ( z-3 )^ 678 = 0
tìm x,y,z biết:
\(\left(x-\frac{1}{5}\right)^{2004}+\left(y+0,4\right)^{100}+\left(z-3\right)^{678}=0\)
Tìm x, y, z
\(\left(x-\frac{1}{5}\right)^{2004}+\left(y+0,4\right)^{100}+\left(z-3\right)^{678}=0\)
Tìm x, y, z biết rằng :
\(\left(x-\frac{1}{5}\right)^{2004}+\left(y+0,4\right)^{100}+\left(z-3\right)^{678}=0\)
\(\left(x-\frac{1}{5}\right)^{2004}+\left(y+0,4\right)^{100}+\left(z-3\right)^{678}=0\)0
Tìm x,y,z biết
\(\left(x-\frac{1}{5}\right)^{2004}+\left(y+0,4\right)^{100}+\left(z-3\right)^{678}=0\)
AI bít giúp mìk vs, thanks trước
\(\left(x-\frac{1}{5}\right)^{2004}+\left(y+0.4\right)^{100}+\left(z-3\right)^{678}=0\)
\(\left(x-\frac{1}{5^{ }}\right)^{2004}+\left(y+0.4\right)^{100}+\left(z-3\right)^{678}=0\)
Tìm x,y,z khi:
a) \(\frac{x-1}{2005}=\frac{3-y}{2006}\) và x-y=4009
b) \(\frac{x}{2}=\frac{y}{3}:\frac{y}{4}=\frac{z}{5}\) và x-y-z=28
c) 3x=y; 5y=4z và 6x+7y+8z=456