Question

1. Tìm x    3.(x-2)+4.(x-3)-6.(x+8)=15

Answer 1

\(3\left(x-2\right)+4\left(x-3\right)-6\left(x+8\right)=15\)

\(\Rightarrow3x-6+4x-12-6x-48=15\)

\(\Rightarrow x-66=15\)

\(\Rightarrow x=81\)

Vậy x = 81

Answer 2

3(x - 2) + 4(x - 3) - 6(x + 8) = 15

x - 66 = 15

x        = 15 + 66

x        = 81

Answer 3

\(3.\left(x-2\right)+4.\left(x-3\right)-6.\left(x+8\right)=15\\ \Leftrightarrow3x-6+4x-12-6x-48=15\\ \Leftrightarrow x-66=15\\ \Leftrightarrow x=81\)