Các câu hỏi tương tự
So sánh A và B
A=\(\frac{8^9+12}{8^9+7}\)và B=\(\frac{8^{10}+4}{8^{10}-1}\)
So sánh
\(A=\frac{8^9+12}{8^9+7}\)
\(B=\frac{8^{10}+4}{8^{10}-1}\)
So sánh :
A = \(\frac{1+2+3+4+5+6}{7+8+9+10+11+12}\) ; B = \(\frac{1+2+3+4+5+6+7}{7+8+9+10+11+12+13}\)
So sánh:
a, A= \(\frac{10^8+2}{10^8-1}\) ; B= \(\frac{10^8}{10^8-3}\)
b, A= \(\frac{8^{10}+1}{8^{10}-1}\) ; B=\(\frac{8^{10}-1}{8^{10}-3}\)
c, A= \(\frac{100^9+4}{100^9-1}\): B= \(\frac{100^9+1}{100^9-4}\)
So sánh A và B:
A = 8^9 + 12/ 8^9 + 7; B = 8^10 + 4/ 8^10 - 1
So sánh:
1/ A= \(\frac{10^9+2}{10^9-1}\) và B =\(\frac{10^9}{10^9-3}\)
2/ A = \(\frac{2015^8+3}{2015^8-2}\)và B=\(\frac{2015^8+4}{2015^8-1}\)
bài 1 So sánha)Afrac{3}{8^3}+frac{7}{8^4} ; Bfrac{7}{8^3}+frac{3}{8^4}b)Afrac{10^{1992}+1}{10^{1991}+1};Bfrac{10^{1993}+1}{10^{1992}+1}c)Afrac{10^7+5}{10^4-8};Bfrac{10^8+6}{10^8-7}d)Afrac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8};Bfrac{1+3+3^2+...+3^9}{1+3+3^2+...+3^8}e)Afrac{2011}{2012}+frac{2012}{2013};Bfrac{2011+2012}{2012+2013}
Đọc tiếp
bài 1 So sánh
a)\(A=\frac{3}{8^3}+\frac{7}{8^4}\) ; \(B=\frac{7}{8^3}+\frac{3}{8^4}\)
b)\(A=\frac{10^{1992}+1}{10^{1991}+1};B=\frac{10^{1993}+1}{10^{1992}+1}\)
c)\(A=\frac{10^7+5}{10^4-8};B=\frac{10^8+6}{10^8-7}\)
d)\(A=\frac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8};B=\frac{1+3+3^2+...+3^9}{1+3+3^2+...+3^8}\)
e)\(A=\frac{2011}{2012}+\frac{2012}{2013};B=\frac{2011+2012}{2012+2013}\)
So sánh :A và B
A=\(\frac{1+2+3+4+5+6}{7+8+9+10+11+12}\) B=\(\frac{1+2+3+4+5+6+7}{7+8+9+10+11+12+13}\)
Trả lời nhanh mk tk:
NU
18 tháng 3 2018 lúc 14:40
Cho \(M=\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+\frac{4}{5}+\frac{5}{6}+\frac{6}{7}+\frac{7}{8}+\frac{8}{9}+\frac{9}{10}\)
So sánh M với 1