Question

1/ 

cho :A=3+3 mủ 2 + 3 mủ 3+...+2008

tìm số tự nhiên n , biết 2A+3=3 mủ n

 

Answer 1

\(A=3+3^2+...+3^{2008}\)

\(\Rightarrow3A=3^2+3^3+...+3^{2009}\)

\(\Rightarrow3A-A=3^{2009}-3\)

\(\Rightarrow2A+3=3^{2009}\)

Vậy n = 2009

Answer 2

\(A=3+3^2+3^3+...+3^{2008}\)

\(\Leftrightarrow3A=3^2+3^3+...+3^{2009}\)

\(\Leftrightarrow3A-A=3^{2009}-3\Leftrightarrow2A+3=3^{2009}\)

Vậy n=2009