a, \(\left(x+1\right)\left(2y+2\right)=8\)
\(\Leftrightarrow x+1;2y+2\inƯ\left(8\right)\)
Tự xét tiếp nhé!
b, \(\left|x-2\right|+\left|2y-4\right|=0\)
Mà \(\hept{\begin{cases}\left|x-2\right|\ge0\\\left|2y-4\right|\ge0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}\left|x-2\right|=0\\\left|2y-4\right|=0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x=2\\y=2\end{cases}}\)
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