Question

1. 3^x. 3²=243

20- [7(x-3)+4]=2

[(6x -39):3].28=5628

Xmũ 50=x

 

 

Answer 1

Câu 2

\(20-\left(7\left(x-3\right)+4\right)=-\left(7x-37\right)\)

\(-\left(7x-37\right)=2\)

\(37-7x=2\)

\(-7x=-35\)

\(\Rightarrow x=5\)

Answer 2

Câu 1:

\(x\in\left(\infty,-\infty\right)\)

\(1.3x.32=96x\)

\(96x=3^5\)

\(96x=243\)

\(32x=81\)

\(\Rightarrow x=2\frac{17}{32}\)

Answer 3

Câu 3 :

\(\frac{6x-39}{3}.28=28\left(2x-13\right)\)

\(28\left(2x-13\right)=2^2.3.7.67\)

\(56x=5992\)

\(\Rightarrow x=107\)