A= 1 - \(\frac{3}{2.10}\)- \(\frac{3}{4.15}\)- \(\frac{3}{6.20}\)- \(\frac{3}{8.25}\)- ... - \(\frac{3}{198.500}\)
cho A=1 - 3/2.10-3/4.25-3/6.20-....-3/198.500
tim A
\(\frac{8^{10}.9^8.25^{25}.7+1024^3.243^3.99.125^{17}}{11.32^5.10^4.15^{18}.25^{15}-10^{30}.25^{11}.27^6}\)
Baif 1a)142 .16x=8xb)3−3.35.3x=38c)(7x 2)−1=3−2Bài 2a)34.1729 .813.192 b)(8.25):(24.132 )c)128.912d)(1 23 −14 ).(45 −34 )2Giups mik nha
1.a,chứng minh 12^4.54^2=36^5
b,10^6-5^7 chia hết cho 59
c,cho S=1+3^1+3^2+3^3…+3^99 chứng minh S chia hết cho 4, S chia hết cho 40
2. Tính: 10^4.27^3/6^4.15^4
Tính A=3/1^2.2^2 + 5/2^2.2^3 + 7/3^2.4^2 +....+ 19/9^2.10^2
CMR : 3/1^2.2^2 + 5/2^2.3^2 + 7/3^2.4^2 + ... + 19/9^2.10^2 < 1
3/1^2.2^2 + 5/2^2.3^2 + 7/3^2.4^2 +...+ 19/9^2.10^2. chung minh nho hon 1
Chứng minh rằng :
\(\dfrac{3}{1^2.2^2}+\dfrac{5}{2^2.3^2}+\dfrac{7}{3^2.4^2}+...+\dfrac{19}{9^2.10^2}< 1\)
