\(1-2+3-4+5-6+...+2019-2020+2021\)
\(=\left(1+3+5+....+2021\right)-\left(2+4+6+...+2020\right)\)
\(=\left(\frac{\left(2021+1\right).1011}{2}\right)-\left(\frac{\left(2020+2\right).1010}{2}\right)\)
\(=\frac{2022.1011}{2}-\frac{2022.1010}{2}=\frac{2022}{2}=1011\)
...
Ra mỗi kết quả:
-1011